file_get_contents无法从正确的url中检索html

Question

I'm trying to get the response json from this api call. For doing this I build the url in the following way:

$currentDate = date("Y-m-d");
$timestamp = date("Y-m-d H:m:s");

$url =  "https://int.soccerway.com/a/block_home_matches?block_id=block_home_matches_30&callback_params=";
$url .= "{\"block_service_id\":\"home_index_block_homematches\",\"date\":\"". $currentDate ."\",";
$url .= "\"display\":\"now_playing\",\"timestamp\":\"". $timestamp . "\"}";
$url .= "&action=filterContent&params=";
$url .= "{\"display\":\"now_playing\"}";

so I executed the request:

$html = file_get_contents($url);
$json = json_decode($html);

I get:

failed to open stream: HTTP request failed! HTTP/1.0 404 Not Found

but the link is correct, infact if you paste the $url you can see the correct response.

What I did wrong?

Answer 1

URL encode just the values that aren't URL parameters. e.g.

$currentDate = date("Y-m-d");
$timestamp = date("Y-m-d H:m:s");

$url =  'https://int.soccerway.com/a/block_home_matches?block_id=block_home_matches_30&callback_params=';
$url .= urlencode('{"block_service_id":"home_index_block_homematches","date":"'. $currentDate . '","display":"now_playing","timestamp":"' . $timestamp . '"}');
$url .= '&action=filterContent&params=';
$url .= urlencode('{"display":"now_playing"}');

It also is a bit easier to use single quotes for the encapsulation, and I would use json_encode to build JSON strings in the future.

A json_encode example would be:

$url =  'https://int.soccerway.com/a/block_home_matches?block_id=block_home_matches_30&callback_params=';
$json['block_service_id'] = 'home_index_block_homematches';
$json['date'] = date("Y-m-d");
$json['display'] = 'now_playing';
$json['timestamp'] = date("Y-m-d H:m:s");
$url .= urlencode(json_encode($json));
$url .= '&action=filterContent&params=';
$url .= urlencode(json_encode(array('display' => 'now_playing')));