All, I've got the following page: http://tinyurl.com/7lzr6qo
The original form code is:
<form id="dj_feedback" name="dj_feedback" action="../test-save-feedback" method="post">
<br>
<h2>How was the Event?</h2>
<hr>
<table><tr><td width="100px" valign="middle">
<b>Person<font color="#FF0000"> * </font></b>
</td><td valign="middle">
<select name="dj_name" id="dj_name">
<option value="original"></option>
<?php
$qrydj = "Select user_id, first_name, last_name from users where role='employee'";
$resultdj = mysql_query($qrydj);
while($resultsetdj = mysql_fetch_array($resultdj)){
?>
<option value="<?php echo $resultsetdj['user_id']; ?>"><?php echo $resultsetdj['first_name']." ".$resultsetdj['last_name']; ?></option>
<?php
}
?>
</select></td>
</tr>
</table>
<button class="submit" name="submit_feedback" value="submit_feedback">Get Paid!</button>
</form>
When I view the dropdown source it has a value on the select and then on my second page all I have is a simple echo statement to view what was passed like this:
<?php
session_start();
$user_id = $_POST['dj_name'];
echo "The user id is: ".$user_id;
?>
However, when I post this the value selected in the dropdown menu doesn't get passed. In other browsers this works perfectly fine however.
Does anyone have any idea why this isn't working properly?
Thanks!