如何从给定值php获取特定参数值

Question

if $url = 'http://yalumalu.com/watch_video.php?v=UXNWH2YA43RU'; is my url,

how to get value in the parameter "V=" ?

I tried using explode url but it returns an empty value? hlp me...

Answer 1

Edited to consider @Brad suggestion

$pos = strpos($url,'?') + 1;

parse_str(substr($url,$pos),$arg);
echo $arg['v'];