drhgzx4727 2018-04-18 03:39
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如何解码这个

I am new to PHP, I am trying to learn it. Actually, I am not getting what is this format and how to get the result from it. below is my code after var_dump:

$data = some array();
var_dump($data);
/*
 object(stdClass)#58 (3) {
    ["jsonrpc"]=> string(3) "2.0"
    ["id"]=> int(1)
    ["result"]=> string(42) "Success"
} 
*/

Now I want the 'result' parameter only as a string. I am trying to do this way:

$reult = $data['result'];

but it is giving Illegal string offset 'result' error.

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  • dongyidao1461 2018-04-18 03:42
    关注
    echo $data->result;
    

    You can use this to echo the object value

    Or you can cast it as array

    var_dump( (array) $data);
    $data=(array) $data;
    echo $data[result];
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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