仅为一条路线的Laravel路线模型绑定

Question

I have a controller with 8 methods. Seven of them use this statement:

$item = Item::findOrFail($id);

However, only one needs a different query:

$item = Item::with('subitem')->findOrFail($id);

I would like to define a route model binding for the first seven of these methods, however, is there a way to somehow tell the Laravel that for the last method I want the ID injected instead of an instance of the Item class? Currently I'm doing the following but its quite bad:

$item = Item::with('subitem')->findOrFail($item->id);

Answer 1

Yes, you can do it easily only by changing the parameter name in your route that is being used for model binding, for example, why not use $item (or something like that) in the routes for which you need model binding so you can bind the model to routes which contains $item parameter, for example:

Route::post('items/{item}', 'ItemController@update');

When binding the model to route, use something like this:

public function boot(Router $router)
{
    parent::boot($router);

    $router->model('item', 'App\Item');
}

So, onle when item parameter is found as route parameter, the Item model would be bound but for the route which needs an ID, use route declaration like this one (Using id as parameter):

Route::post('items/{id}', 'ItemController@whatever');

In ItemController@whatever method you'll get the id from route:

public function whatever($id)
{
    // $id would be an integer value for $id not a model
}