dsc6517 2015-10-06 14:14
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清除Jquery CodeIgniter中的任何Previous错误消息

I am posting this question after searching alot on google.I am posting my FORM on Jquery POST method and doing validation in codeigniter.

If a field is empty,it show me error message,BUT when i fill that field and click again,this time there is no error but it do not remove previous error message. Here is my code

 var parameters = $("#frm_rexpert").serialize();
     var form = $("#frm_rexpert");
     $.post(siteurl+'/services/req_expert', parameters, function(data) {
        if (data.status == true) {
            //show success message
            $("#msg_exp").show();
            setTimeout(function() { $("#msg_exp").hide(); }, 5000);
        }else{
            $.each(data.errors, function(key, val) {

                $('[name="'+ key +'"]', form).after(val);

            })
        }
    }, "json");

On server side

       $this->form_validation->set_rules($rules);
        $this->form_validation->set_error_delimiters('<div class="error">', '</div>');
        if ($this->form_validation->run())
        {//do your code
        }else{
       $errors = array();
            // Loop through $_POST and get the keys
            foreach ($this->input->post() as $key => $value)
            {
                // Add the error message for this field
                $errors[$key] = form_error($key);
            }
            $response['errors'] = array_filter($errors); // Some might be empty
            $response['status'] = FALSE;
          }
     header('Content-type: application/json');
     exit(json_encode($response));

MY Question is "If there is no error,I need to clear all old error messages"

  • 写回答

2条回答 默认 最新

  • dongmen1925 2015-10-06 14:35
    关注

    If you want to clear the console, you just need to use console.clear() inside the success block. If you also want to erase all the things inserted by previous errors, you need to remove what is after each form input. Something like this:

     $.post(siteurl+'/services/req_expert', parameters, function(data) {
        if (data.status == true) {
            $('.error', form).remove(); //removes previous errors' notices
            console.clear(); //clears the debug console
            //show success message
            $("#msg_exp").show();
            setTimeout(function() { $("#msg_exp").hide(); }, 5000);
        } ...
    

    Edit: I changed the selector to match your elements with errors.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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