doudi1978 2012-12-13 13:05
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PHP脚本没有将值插入数据库

Below I have a modules drop down menu where it gets a list of modules from the db an obviously displays them in a drop down menu:

$active = 1;

 $sql = "SELECT ModuleId, ModuleNo, ModuleName FROM Module WHERE ModuleActive = ? ORDER BY ModuleNo"; 

 $sqlstmt=$mysqli->prepare($sql);

 $sqlstmt->bind_param("i",$active);

 $sqlstmt->execute(); 

 $sqlstmt->bind_result($dbModuleId, $dbModuleNo, $dbModuleName);

 $modules = array(); // easier if you don't use generic names for data 

 $output = ""; 
 $moduleHTML = "";  
 $moduleHTML .= '<select name="module" id="modulesDrop">'.PHP_EOL;
 $moduleHTML .= '<option value="">Please Select</option>'.PHP_EOL;  

 while($sqlstmt->fetch()) 
 { 
     $moduleno = $dbModuleNo;
     $module = $dbModuleId;
     $modulename = $dbModuleName; 
     $moduleHTML .= "<option value='".$module."'>" . $moduleno . " - " . $modulename . "</option>".PHP_EOL;  

         if (isset($_POST['module']) && ($_POST['module'] == $module)) {
    $output .= "<p><strong>Selected Module:</strong> " . $moduleno .  " - "  . $modulename . "</p>";
}
  } 

  $moduleHTML .= '</select>'; 

But the problem I am getting below is that when I try to insert the selected module into the database, it is unable to do it and hence ModuleId is null. Why can it not insert the selected module into the database?

if (isset($_POST['module'])) {

$_SESSION['module'] = $_POST['module'];

}

if($_SERVER['REQUEST_METHOD'] == 'POST')

{



            $insertsql = "
      INSERT INTO Session
        (ModuleId)
      VALUES
        (?)
    ";
    if (!$insert = $mysqli->prepare($insertsql)) {
      // Handle errors with prepare operation here
    }


        $insert->bind_param("i", $_SESSION['module']);

        $insert->execute();

        if ($insert->errno) {
          // Handle query error here
        }

        $insert->close();



}

ModuleId is an INT field

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1条回答 默认 最新

  • douxia2137 2012-12-13 13:28
    关注

    try this

        if ($insert = $mysqli->prepare($insertsql)) {
    
    
        $insert->bind_param("i", real_escape_string($_SESSION['module']));
    
        $insert->execute();
        $insert->close();
        }
        else  {
          // Handle query error here
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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