douyanguo7964 2009-12-15 00:12
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PHP Checkbox数组

All,

When a form gets posted, I get some checkbox values like the below:

 [chk0] => Array ( 
    [1] => on 
    [57] => on 
    [83] => on 
  ) 
 [chk1] => Array ( 
    [69] => on 
    [71] => on
 )
 [chk1001] => on 
 [chk1005] => on
 [chk1008] => on

Using PHP,How can I construct a JSON request with 2 arrays like this by using the above variables? All checkboxes are prefixed with "chk". If the checkbox is an array and has values, the first JSON request should be generated. For all those which are not arrays, it should generate the second one.

//JSON Request 1
       "data1":
            [
                {
                    "checkboxval": true,
                    "id": 1
                },
                {
                    "checkboxval": true,
                    "id": 57
                },
                {
                    "checkboxval": true,
                    "id": 83
                },
                {
                    "checkboxval": true,
                    "id": 69
                },
                {
                    "checkboxval": true,
                    "id": 71
                }
            ]

//JSON Request 2:
   "data2":
        [
            {
                "checkboxval": true,
                "id": 1001
            },
            {
                "checkboxval": true,
                "id": 1005
            },
            {
                "checkboxval": true,
                "id": 1008
            }
        ]
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1条回答 默认 最新

  • duandong1963 2009-12-15 00:20
    关注
    $data = array(
        "data1" => array(),
        "data2" => array(),
    );
    foreach($_POST as $key => $value)
    {
        if(preg_match('/^chk/',$key))
        {
            if(is_array($value))
            {
                foreach($value as $id => $on)
                    $data["data1"][] = array("checkboxval"=>true,"id"=>$id);
            }
            else
                $data["data2"][] = array("checkboxval"=>true,"id"=>str_replace("chk","",$key));
        }
    }
    $json = json_encode($data);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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