PHP缓存结构（如果是HIT则跳过代码块）

Question

Basically, I am implementing own cache system. Ideally, it'll look like this:

$CACHE->start($name);
   //CODE
$CACHE->end();

But that is a holy grail that I do not hope to find. Basically, the $CACHE->start() checks if cache is a hit or a miss, and whether it is a hit, it skips the //CODE until $CACHE->end().

The best I have come so far, is:

if ($CACHE->start($name)) {
   //CODE
}
$CACHE->end();

Since PHP supports anonymous functions, I was thinking of:

$CACHE->make($name, function() {
   //CODE
});

But this code has a problem that code is not in the same variable scope. Any chance to bypass that?

Update: I have since switched to ruby, which allows to pass the block to a function, being perfect for this task.

Answer 1

Zend Framework includes a cache that skips $cache->end() by assuming the remainder of the page is part of the cached content.

// Default cache ID is calculated from $_SERVER['REQUEST_URI']
$zendPageCache->start();

// ....

// No need for end

It doesn't fit all use-cases though.

(A modified version of my comment)