dongwei1895 2014-07-10 08:55
浏览 19
已采纳

PHP日期差异,在数组之间保存每一天

I have an array which each element contains a startdate and enddate formated in 'dd.mm.yy'.

 Array
    (
        [0] =
            (
                [date_start] = 23.07.2014
                [date_end] = 02.08.2014
            )
     )

Now i need to build an array that will contain every day between date_start and date_end to validate them later.

Now my question is how can i calculate every day between those dates and save it to an array ?

  • 写回答

5条回答 默认 最新

  • douzi1991 2014-07-10 09:05
    关注

    This should work:

    $startDate = new DateTime('2014-05-01');
    $endDate  = new DateTime('2014-06-02');
     // calculate diff
    $diff = $startDate->diff($endDate);
    $daysDiff = $diff->days;
    
    
    for ($i = 0; $i < $daysDiff; $i++) {
        // clone so the original date will not be changed
        $currentDate = clone $startDate;
        $currentDate->modify('+'.$i.' days');
        echo $currentDate->format('Y-m-d H:i:s')."
    ";
    }
    

    Now you only have to make this for every array entry and save it to an array

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(4条)

报告相同问题?

悬赏问题

  • ¥15 c语言怎么用printf(“\b \b”)与getch()实现黑框里写入与删除?
  • ¥20 怎么用dlib库的算法识别小麦病虫害
  • ¥15 华为ensp模拟器中S5700交换机在配置过程中老是反复重启
  • ¥15 java写代码遇到问题,求帮助
  • ¥15 uniapp uview http 如何实现统一的请求异常信息提示?
  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?