donglv6747 2014-04-12 12:06
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MySQL的顺序是多少就像一个字符串

I have the following MySQL query:

SELECT * FROM users WHERE name LIKE '%jack%'

I want it to order by how much it's like jack so

  1. jack
  2. jacker
  3. majack

I can also use PHP.

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  • douyuan1049 2014-04-14 15:39
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    I think you can accomplish what you want by using full text search function in mysql. Your query will be like this:

    SELECT name, MATCH (name) AGAINST ('jack') as score 
    FROM users ORDER BY score DESC;
    

    There are some conditions you need to take into consideration when using full search text:

    • The mysql engine should support this functions. I think InnoDB 5.6 and MYISAM 5.5 support that.
    • You have to add a FULLTEXT index in your table definition.

    You can see a working demo here: http://sqlfiddle.com/#!9/72bf5/1

    More info about full search text in MySQL here: http://dev.mysql.com/doc/refman/5.0/en/fulltext-natural-language.html

    Also, here is a working example I wrote on PHP using similar_text and sorting array functions: http://ideone.com/UQpBFk

    Hope it helps!

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