dongxu6418 2008-11-07 11:29
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显示从数据库查询返回的空字段的默认值的最佳方法?

Is there a better way to write this code?

I want to show a default value ('No data') for any empty fields returned by the query:

$archivalie_id = $_GET['archivalie_id'];

$query =    "SELECT 
                a.*, 
                ip.description AS internal_project,
                o.description AS origin,
                to_char(ad.origin_date,'YYYY') AS origin_date  

            FROM archivalie AS a 
            LEFT JOIN archivalie_dating AS ad ON a.id = ad.archivalie_id                
            LEFT JOIN internal_project AS ip ON a.internal_project_id = ip.id
            LEFT JOIN origin AS o ON a.origin_id = o.id               

            WHERE a.id = $archivalie_id";

$result = pg_query($db, $query);

while ($row = pg_fetch_object($result))
{
    $no_data = '<span class="no-data">No data</span>';

    $internal_project = ($row->internal_project != '') ? $row->internal_project : $no_data; 
    $incoming_date = ($row->incoming_date != '') ? $row->incoming_date : $no_data; 
    $origin = ($row->origin != '') ? $row->origin : $no_data; 
}
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4条回答 默认 最新

  • duanjiao3686 2008-11-07 11:35
    关注

    You could use a small helper function

    function dbValue($value, $default=null)
    {
        if ($default===null) {
            $default='<span class="no-data">No data</span>';
        }
        if (!empty($value)) {
            return $value;
        } else {
            return $default;
        }
    }
    
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