php strtotime和锻炼多年？

Question

I have a date stored in my mysql database and I can workout the days since the date like so,

 ceil(time() - strtotime($account['joined']) / 60 / 60 / 24 % 365);

But how can I work out the years, since years is the highest format of time, since after that it is millenia and such?

The variable is one such as:

2011-10-06 22:01:57

Thanks

Answer 1

Use date("Y")

<?php 
$time = strtotime("1 Jan 2001 1:11:11"); 
echo "Years since time: ".(date("Y") - date("Y", $time));

http://sandbox.phpcode.eu/g/220fe/1