duandao2083 2018-05-09 20:53
浏览 62
已采纳

在Symfony中键入提示json对象

In my Symfony 2.3 project, I have a curl function that receives JSON data from an API and passes this data as a parameter to another function. Currently, the function that accepts the JSON object looks like this:

public function updateCountries($data)
{
    foreach (json_decode($data, true) as $key => $value) {
        (do something)
    }
}

I'd like to add a type hint to the $data parameter to indicate that this is a JSON object, but a "JSON" type doesn't seem to exist. Is there a type hint that would work?

  • 写回答

1条回答 默认 最新

  • drgc9632 2018-05-09 21:09
    关注

    PHP doesn't support JSON as a type. $data would come in as a string and be converted to a array when you call json_decode() on it. You can make a method that takes a json string as a argument and returns a array. Then type hit updateCountries with Array.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥20 西门子S7-Graph,S7-300,梯形图
  • ¥50 用易语言http 访问不了网页
  • ¥50 safari浏览器fetch提交数据后数据丢失问题
  • ¥15 matlab不知道怎么改,求解答!!
  • ¥15 永磁直线电机的电流环pi调不出来
  • ¥15 用stata实现聚类的代码
  • ¥15 请问paddlehub能支持移动端开发吗?在Android studio上该如何部署?
  • ¥20 docker里部署springboot项目,访问不到扬声器
  • ¥15 netty整合springboot之后自动重连失效
  • ¥15 悬赏!微信开发者工具报错,求帮改