doulachan8217 2014-09-04 05:34
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在php中验证url

I have the following seems simple code in php; but the ptoblem is that it shows all valid links as "not valid"; any help appreciated:

<?php
   $m = "urllist.txt";
   $n = fopen($m, "r");
   while (!feof($n)) {
      $l = fgets($n);
      if (filter_var($l, FILTER_VALIDATE_URL) === FALSE) {
          echo "NOT VALID - $l<br>";
      } else {
          echo "VALID - $l<br>";
      }
   }
   fclose($n);
?>
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4条回答 默认 最新

  • douding6266 2014-09-04 06:01
    关注

    The string returned by fgets() contains a trailing newline character that needs to be trimmed before you can validate it. Try out following code, I hope this will help you:

    <?php
      $m = "urllist.txt";
      $n = fopen($m, "r");
      while (!feof($n)) {
        $l = fgets($n);
        if(filter_var(trim($l), FILTER_VALIDATE_URL)) {
          echo "VALID - $l<br>";
        } else {
          echo "NOT VALID - $l<br>";
        }      
      }
      fclose($n);
    ?>
    

    I have tried with following urls:

    http://stackoverflow.com/
    https://www.google.co.in/
    https://www.google.co.in/?gfe_rd=cr&ei=bf4HVLOmF8XFoAOg_4HoCg&gws_rd=ssl
    www.google.com
    http://www.example.com
    example.php?name=Peter&age=37
    

    and get following result:

    VALID - http://stackoverflow.com/ 
    VALID - https://www.google.co.in/ 
    VALID - https://www.google.co.in/?gfe_rd=cr&ei=bf4HVLOmF8XFoAOg_4HoCg&gws_rd=ssl 
    NOT VALID - www.google.com 
    VALID - http://www.example.com 
    NOT VALID - example.php?name=Peter&age=37 
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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