Json用PHP mysql和Jquery

Question

I have a strange problem..

When i try to access my json code with the corresponding number [0], [1] etc.. I just get the first character of the object.

First of my code:

test2.php

if(isset($_POST['getCustomersArray'])){
$runQuery = mysql_query($Query) or
        die("SQL: $Query)<br />".mysql_error()); 
$numrows = mysql_num_rows($runQuery); 
$array = array(array());

for($i = 0;$i <= 2; $i++){
    $row = mysql_fetch_array($runQuery);
    $array[$i]['namn'] = $row['fornamn'];

}
    print json_encode($array);
}

scriptfile.js

$.ajax({
    type:"POST",
    url: "test2.php",
    data: "getCustomersArray=true",
    datatype: "JSON",
    cache: false,
    success: function(json) {
            console.log(json[0]);
     }
});

The result (from console.log(json[0])):

[

The result from just console.log(json):

[{"namn":"the first name"},{"namn":"The secound name"},{"namn":"the third name"}]

Im not sure why the squarebrackets are there but maybe they should be?

Ive been fuzzing with this problem for a while now and im sure its something stupid. Please help.

Answer 1

You have an incorrect option in the AJAX settings,

datatype: "json",

It should be:

dataType: "json",