dsc80135 2014-04-02 22:28
浏览 74
已采纳

AJAX / jQuery / PHP / MySQL - 如何更新数据库

I need to update a database using AJAX so don't have my page be reloaded. I can't find what's wrong and unexpectedly I get a success message back but a database doesn't get updated.

JS:

$('.start-time-class').submit(function() {                  

var startTime = "11:30";                
var projectID = 17;             
var userID = 2;             

$.ajax({
 url:'functions/starttime.php',
 data:{startTime:startTime,projectID:projectID,userID:userID},  // pass data 
 dataType:'json',
 success:function(){
  // something
 }                      
});         

});

PHP:

$con = mysqli_connect('localhost','smt','smt','smt');
if (!$con)
{
die('Could not connect: ' . mysqli_error($con));
}

$startTime = $_GET['startTime'];
$projectID = $_GET['projectID'];
$userID = $_GET['userID'];

mysqli_select_db($con,"ajax_demo");
$sql = "INSERT INTO 'uc_project_time'('userID', 'projectID', 'startTime') VALUES (". $userID .", ". $projectID .", ". $startTime .")";

$result = mysqli_query($con,$sql);      

mysqli_close($con);
  • 写回答

2条回答 默认 最新

  • doubi2014 2014-04-02 22:34
    关注

    Don't use quotes for table or column names

    Use:

    $sql = "INSERT INTO uc_project_time (userID, projectID, startTime) VALUES ('$userID', '$projectID', '$startTime')";
    

    or

    $sql = "INSERT INTO uc_project_time (userID, projectID, startTime) VALUES ('".$userID."', '".$projectID."', '".$startTime."')";
    

    And do sanitize your code:

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 一个服务器已经有一个系统了如果用usb再装一个系统,原来的系统会被覆盖掉吗
  • ¥15 使用esm_msa1_t12_100M_UR50S蛋白质语言模型进行零样本预测时,终端显示出了sequence handled的进度条,但是并不出结果就自动终止回到命令提示行了是怎么回事:
  • ¥15 前置放大电路与功率放大电路相连放大倍数出现问题
  • ¥30 关于<main>标签页面跳转的问题
  • ¥80 部署运行web自动化项目
  • ¥15 腾讯云如何建立同一个项目中物模型之间的联系
  • ¥30 VMware 云桌面水印如何添加
  • ¥15 用ns3仿真出5G核心网网元
  • ¥15 matlab答疑 关于海上风电的爬坡事件检测
  • ¥88 python部署量化回测异常问题