如何回显我们用file_get_contents读取的数据

Question

i want to check remote url's page contents. IF remote site's page content contains string http://yahoo.com set $qqq = YH if not contains $qqq = NOYH. i am not talking about "url of that page" im talking about page content of url

$url = "'".$get['url']."'";
$needle = "http://yahoo.com/";
$contents = file_get_contents($url);
if(stripos($contents, $needle) !== false) {
    $qqq = "YH";
}

But it's not working. Can anybody help me with the correct syntax? thanks..

Answer 1

It think your code won't work. For a number of reasons:

1. In your first line, you create a string, that contains single-quotes. So basically, $url contains something like 'http://url.here'. If you pass this to file_get_contents you get an error:

   $url = "'http://www.google.com'";
   echo file_get_contents($url);
   
   Warning: file_get_contents('http://www.google.com/'): failed to open stream: 
   No such file or directory in ...
   

2. You said want to check whether $url contains a certain string. But you are checking whether the document the URL is pointing to, contains this string.

3. Maybe you mean $_GET instead of $get to retrieve the parameter url that is contained in the URL?

Ok, I read from the comments that you indeed want to search for the string in the content. Still, the first line of code is wrong, so it is probably:

$needle = "http://yahoo.com/";
$contents = file_get_contents($get['url']);
if(stripos($contents, $needle) !== false) {
    $qqq = "YH";
}

(<?= $qqq ?> should work as it is).