doqw89029 2015-10-01 14:06
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动态查询ORM Laravel 4.2

Alright I have a GeneralModel written in CodeIgniter and a friend asked me if I could convert it into Laravel 4.2 for him. I was working on this and I think I have most of it correct but I am getting stuck at the select statement.

In CodeIgniter I have the following:

public function getData($table, $multiple = 1, $field = FALSE, $val = FALSE){

    if($field != FALSE){
        // WHERE in case of FIELD / VAL :)
        $this->db->where($field, $val);
    }

    $query = $this->db->get($table);

    if($multiple == 1){
        // Multiple rows
        return $query->result_array();
    } else {
        // One row
        return $query->row_array();
    }
}

Does anyone here knows how I can convert this function into Laravel 4.2 syntax? I currently have:

public function getData($table, $multiple = 1, $field = FALSE, $val = FALSE){
    $result = DB::table($table);

}

I got stuck pretty quickly since I have no idea how I can achieve the same in Laravel 4.2 with splitting up the sections of the query like I did with CodeIgniter.

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2条回答 默认 最新

  • drqn5418 2015-10-01 14:13
    关注

    You can chain methods in the same way:

    public function getData($table, $multiple = 1, $field = FALSE, $val = FALSE)
    {
        $query = DB::table($table);
    
        if ($field != FALSE) {
            // WHERE in case of FIELD / VAL :)
            $query->where($field, $val);
        }
    
        if ($multiple)
            return $query->get();
        else
            return $query->first();
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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