dps57553 2015-01-16 19:22
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MySQL和PHP:仅显示表中的第一个字段

I am working with PHP and MySQL. I need to retrieve all the rows from the database table and display on the browser in tabular form, but for some reason only the First field in the table gets displayed and others fields don't show up or are not pulled from the database.

Here is my PHP code.

<?php
include("DBConn.php");

$result = mysql_query("SELECT * FROM new_table");

if(!$result) {
  die("Database query failed: " . mysql_error());
}

echo "<table>
<caption>Signal Data:</caption>
<thead>
<tr>
   <th scope=\"col\">TagName:</th>  
  <th scope=\"col\">Enabled</th>  
  <th scope=\"col\">EU Value</th> 
</tr>
</thead>
<tbody>";

while ($row = mysql_fetch_array($result)) {

$tag = $row["TagName"];
$status = $row["Enabled"];
$Ev = $row["EUValue"];

echo "<tr>
 <th scope=\"row\">$tag</th>
 <td>$status</td>
 <td>$EV</td>
   </tr>";
}
echo  "</tbody></table>";
?>

What is wrong with this PHP code? The code itself executes fine without any error.

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1条回答 默认 最新

  • dqy1265 2015-01-16 19:24
    关注

    The third row can be corrected by matching the case of the variable names. You are assigning the value to a variable named $Ev (lowercase 'v'):

    $Ev = $row["EUValue"];
    

    but attempting to use a variable named $EV (uppercase 'V'):

    <td>$EV</td>
    

    For both the second and third fields, ensure that Enabled and EUValue exactly match the names of the fields in your database, including case and spelling.

    Finally, check the data itself to ensure that the fields have data in your database, and that the data is displayable in your HTML output.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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