doucao1066 2014-12-02 16:43
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php DOMDocument - 将子元素列出到数组

For the following HTML:

<html>
<body>
<div whatever></div>
<div id="archive-wrapper">
<ul class="archive-list">
    <li><div><a href="#1">A</a></div></li>
    <li><div><a href="#2">B</a></div></li>
    <li><div><a href="#3">C</a></div></li>
</ul>
</div>
</body>

How could I retrieve, with PHP DOMDocument (http://php.net/manual/es/class.domdocument.php), an array containing (#1,#2,#3) in the most effective way? It's not that I did not try anything or that I want an already done code, I just need to know some guidelines to do it and understand it on my own. Thanks :)

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  • dpfad62426 2014-12-02 17:15
    关注

    A simple example using php DOMDocument -

    <?php
$html = <<<HTML
<html>
<body>
<div whatever></div>
<div id="archive-wrapper">
<ul class="archive-list">
    <li><div><a href="#1">A</a></div></li>
    <li><div><a href="#2">B</a></div></li>
    <li><div><a href="#3">C</a></div></li>
</ul>
</div>
</body>
HTML;

$dom = new DOMDocument();
$dom->loadHTML($html);

//get all links
$links = $dom->getElementsByTagName('a');
$linkArray = array();

//loop through each link
foreach ($links as $link){
    $linkArray[] = $link->getAttribute('href');
}

    edit
    to get only the links inside ul->li, you could do something like -

    $dom = new DOMDocument();
$dom->loadHTML($html);

$linkArray = array();

foreach ($dom->getElementsByTagName('ul') as $li){
    foreach ($li->getElementsByTagName('li') as $a){
        foreach ($a->getElementsByTagName('a') as $link){
            $linkArray[] = $link->getAttribute('href');
        }
    }
}

    or if you just want the 1st ul you could simplify to 

    //get 1st ul using ->item(0)
$ul = $dom->getElementsByTagName('ul')->item(0);
foreach ($ul->getElementsByTagName('li') as $li){
    foreach ($li->getElementsByTagName('a') as $a){
        $linkArray[] = $a->getAttribute('href');
    }
}
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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