PHP Preg_replace占位符

Question

Hi I'm writing something for handling my views an I need a preg_replace here, but i can't seem to get it working so I've scrapped the code.

the strings I am trying to replace are dynamic based on a template, e.g.

{{name}} is {{age}} years old

And the passed information into the function is an array e.g.

array( 'name' => 'John Doe', 'age' => '27' );

The pattern I have so far is \{{([a-zA-Z0-9]+)\}} however this only seems to match one pair of braces.

I'm also having a problem looping through results in preg_match_all..

Thanks in advance

Answer 1

preg_replace_callback seems like a good candidate.

$str = "{{name}} is {{age}} years old";
$values = array( 'name' => 'John Doe', 'age' => '27' );
echo preg_replace_callback("/\{{([a-z0-9]+?)\}}/i", function ($result)
use ($values) {
   if (isset($result[1])) {
      return $values[$result[1]];
   }
}, $str);

The main issue is that {{[a-z]+}} will match from {{name ... age}}. Using the ? makes the + reluctant so it only matches up to the first } rather than the last.