donglu3243 2013-12-06 01:09
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输出单个变量时,数组到字符串转换错误

I have a funny error while I'm trying to output a single variable assigned from database.

I'm querying a top id from database and assigning it to a variable. Here:

    $ID_Query = "SELECT DISTINCT MAX(pict_id) FROM picts;";
$temprID = mysql_query( $ID_Query, $Connection ) or die("ERROR: ".mysql_error());
$myID = mysql_fetch_row( $temprID );

But when I'm trying to pass it to the query or simply output $myID I'm getting the Array to string conversion error.

I tried to run the query in mysql and it returns a single value. Where is my mistake?

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  • dsh102123 2013-12-06 01:11
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    While the query returns a single value, fetch_row doesn't - it returns a row (who thought?) containing only one field

    $result = mysql_fetch_row($temprID);
    $myID = $result[0];
    

    Also keep in mind that mysql_* functions are officially deprecated and hence should not be used in new code. You can use PDO or MySQLi instead. See this answer on SO for more information.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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