doumen9709 2013-11-08 12:38
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使用for循环在PHP中创建一个对象数组

I am trying to get data from mysql data, create objects from it. Here I have written some code. I am getting thing's details from a database. Now for each result I want an object to be created which is finally merged with an array output. This $output array is finally outputted as json.

I am getting error :

array_merge(): Argument #2 is not an array

How to create arrays of objects in PHP ?

public function getDetails()    //This is a class function
{
    $query = "SELECT * FROM `thing` WHERE `id` = :thingId";
    $stmt = $dbh->prepare ( $query );
    $stmt->bindParam ( ":thingId" , $_GET['thingId']  );
    $stmt->execute ( );
    $rslt  =  $stmt->fetch ( );
    $thingName  = $rslt['name'];
    $thingOwnerId = $rslt['userId'];
    $thingDescription = $rslt['thingDescription'];

    // Getting the thing owner details
    $query = "SELECT * from `user` WHERE ( `id` = :id ) ";    
    $stmt = $dbh->prepare( $query );
    $stmt->bindParam ( ":id" , $thingOwnerId );
    $stmt->execute(  );
    $rslt = $stmt->fetch ( );
    $thingOwnerName = $rslt['firstName']." ".$rslt['lastName'];
}

$query = "SELECT * FROM `things` ; ";
$s = $dbh->prepare($query);
$s->execute();
$r = $s->fetchAll();
foreach($r as $r1)
{
    $newThing = new Thingy($r1['id']);
    $newThing->getDetails();
    $output =  array_merge($output,$newThing);
}

$output2 = json_encode($output);
header('content-type: application/json');
echo $output2;
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3条回答 默认 最新

  • douzhi1972 2013-11-08 12:44
    关注

    You could do the following:

    $output = [];
    foreach($r as $r1)
    {
        $newThing = new Thingy($r1['id']);
        $newThing->getDetails();
        $output[] = $newThing;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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