计算给定时间戳集的持续时间

Question

I have a set of intime and outtime, and i want to calculate the duration between the intime and outtime and add all the duration to get the total duration.
example:

Array
    (
    [1] => Array
        (
            ['intime'] => 1342086993
            ['outime'] => 1342087585
        )

    [3] => Array
        (
            ['intime'] => 1342087669
            ['outtime] => 1342096165
        )

    [5] => Array
        (
            ['intime'] => 1342096339
            ['outime'] => 1342096345
        )
    )

$total_duration = 0;
foreach($logArray as $log)
{
  $duration = $log['outime'] - $log['intime'];
  $total_duration += $duration;
}

$duration_hrs = $total_duration/3600;
echo 'Time spend in hrs :'.$duration_hrs;

but this is not giving me the proper duration. is there any other way to do so.

Answer 1

Your syntax free script, works for me fine:

<?php

    $logArray = Array (
        1 => Array (
            'intime' => 1342086993,
            'outime' => 1342087585
        ),
        3 => Array (
            'intime' => 1342087669,
            'outime' => 1342096165
        ),
        5 => Array (
            'intime' => 1342096339,
            'outime' => 1342096345
        )
    );

    $total_duration = 0;
    foreach( $logArray as $log ) {
      $duration = $log[ 'outime' ] - $log[ 'intime' ];
      $total_duration += $duration;
        echo $duration / 3600 . "<br />";
    }

    $duration_hrs = $total_duration / 3600;
    echo 'Time spend in hrs: ' . $duration_hrs;

?>

And the output:

0.16444444444444
2.36
0.0016666666666667
Time spend in hrs: 2.5261111111111 

Seems like your time format is not right: 13, July 2012 04:04:32 PM should be 13. July 2012 04:04:32 PM for

strtotime('13. July 2012 04:04:32 PM')

to work right. It should give 1342195472 instead of you 1342168834. So check your time formats that are generating wrong microtimes