dongtuan8547 2011-11-12 00:46
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PHP:提取目录中文件的所有文件名的各个部分

I'd like to be able to loop over all of the files within a directory (the one the script is in) and extract portions of the name and turn it into CSV readable.

From:

ch-026-Metallic-Morphing Mauve-14pt.jpg

To:

ch-026, Metallica-Morphing Mauve-14pt

...or however Excel or Numbers would be able to read it.


At the request of a couple of you, I'll clarify that I want to cut out the second "-" dash and replace it with a comma and space.

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  • dongyuruan2957 2011-11-12 00:58
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    First, use

    $fileList = scandir( $directoryPath );
    

    to scan the directory. Then loop like this

    foreach( $fileList as $fileName ) {
     ...
    }
    

    Finally, use preg_match to match entries. Generally:

    $subject = "abcdef";
    $pattern = '/^def/';
    preg_match($pattern, fileName, $matches, PREG_OFFSET_CAPTURE);
    print_r($matches);
    

    In your case a pattern like

    $pattern = '/^ch-\d*-(.*)-\d*pt\.jpg$/';
    

    might do the job.

    Finally, use the information provided in $matches to write the CSV file.

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