duancenxie2233 2011-07-26 15:15
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PHP OOP Mysql查询

I'm quite new to PHP OOP and I have a question regarding a simple MYSQL query. I have an index.php page where I want to output my results from my query.class file.

Here is my method,

 public function Query($rowName) {

   $q = mysql_query("SELECT * from p_tuts");

   while($row = mysql_fetch_array($q)) {

       echo $row[$rowName];
   }
 }

Now this works fine and I can call it though my index.php file

$Database->Query('tut_content');

But my issue is I want to wrap each content block in DIV containers and don't want to have to echo the HTML code in the class file, so I want to really echo the row's data in the index file, but unsure how to do this.

Kind regards

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  • duanjiong2021 2011-07-26 15:18
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    Pass the rows back as an array.

    public function Query($colName) {
    
        $q = mysql_query("SELECT * from p_tuts");
        $rows = array();
        while($row = mysql_fetch_assoc($q)) {
            $rows[] = $row[$colName];
        }
        return $rows;
    }
    

    It's better this way anyway, because it keeps database code away from output code (i.e. echo).

    Then output it like so:

    <?php
    $results = $Database->Query('tut_content');
    foreach ($results as $result): ?>
        <div><?php echo $result; ?></div>
    <?php endforeach; ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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