douxing9228 2015-04-29 15:22
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PHP为foreach()提供的参数无效

I have this array:

    $y_exceptions = array(
    "lay",
    "interlay",
    "display",
    "delay",
    "obey",
    "decay",
    "play",
    "slay"
);

I'm checking if a word is in my array like this:

foreach($y_exceptions as $thisException) {

Which throws the error

Invalid argument supplied for foreach()

What have I done wrong?

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1条回答 默认 最新

  • douwen3198 2015-04-29 19:42
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    $y_exceptions needs to be an array for it to be processed by a foreach loop. It is possible that $y_exceptions was set to null before the foreach loop. A null is not treated as an array, which the foreach expects—hence the warning.

    On solution would be stricter validation before the foreach:

    if (!is_array($y_exceptions)) {
        // throw an exception
    }
    

    Alternatively, you could instruct the foreach loop to run $y_exceptions as an array, though this may cause errors downstream:

    foreach ((array) $y_exceptions as $thisException) {
        // do stuff
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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