如果PHP / YII中不为空，则显示字段

Question

I used to code with Groovy ... I found that this 'feature' (no idea what they called it) so fun n nice (I heard they implemented this on C# too).

for example ... I want to display person neighbour name

I just type

println person?.neigbour?.name ; 

it means if the neighbour is empty / blank .. it didn't display anything .

how to do this in php 5/yii?

example:

instead of typing long codes like '/>

Would it be better to type like '/>

Answer 1

In the first place I think this is no Yii issue, but simply PHP. Assuming, that you use Yii with nice models, there it would go sth like this:

if($person && $person->neighbour && !empty($person->neighbour->name))  {
   echo $person->neighbour->name;
}

a shortcut for this may be (not so nice):

echo $person ? ($person->neighbour ? ($person->neighbour->name ? $person->neighbour->name : "" ) : ""  ) : "";