dsx58940 2013-12-05 14:36
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PDO错误sql状态42000 [重复]

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I have query function in model:

public function query($qry, $params = array()) {
        try {
            $pdo = $this->prepare($qry);
            $pdo->execute($params);

            return $pdo->fetchAll(PDO::FETCH_OBJ);
        }
        catch (PDOException $e) {
            return '<div class="error message">' . $e->getMessage() . '</div>';
        }
    }

Where I want to INSERT some data to table with this code:

$email = $_POST['email'];
$key = $this->key_generator();
$password = sha1($_POST['password']);

$qry = "
    INSERT INTO users 
    (email, password, key) 
    VALUES (:email, :password, :key)
";

$params = array(
    ':email' => $email, 
    ':password' => $password, 
    ':key' => $key
);

$result = $this->query($qry, $params);

Note: this is only testing code ...

I catch exception:

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key) VALUES

I can't figure out where is syntax error near key).

</div>
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  • dongyong1942 2013-12-05 14:40
    关注

    You should use backtick(`) symbol to enclose every column name since it may contain the mysql key word in your query; password and key are keywords of mysql.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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