dongpo0409 2015-06-06 03:27
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为什么我的foreach不会工作?

$subSpecialties = $this->_db->get('users_subspecialties',array('user_id', '=', $this->_data->id));

print_r($subSpecialties);

foreach ($subSpecialties as $subSpecialty) {
    echo "THIS CODE IS GENERATED FROM INSIDE FOREACH";
}

The first line gets records from my users_subspecialties table

I then used print_r to check the records found.

The output is shown below:

DB Object ( [_pdo:DB:private] => PDO Object ( ) [_query:DB:private] 
=> PDOStatement Object ( [queryString] => SELECT * FROM 
users_subspecialties WHERE user_id = ? ) [_error:DB:private] => 
[_results:DB:private] => Array ( [0] => stdClass Object ( [user_id] 
=> 1 [subspecialty_id] => 2 ) [1] => stdClass Object ( [user_id] => 1 
[subspecialty_id] => 3 ) ) [_count:DB:private] => 2 )

Last line is my for-each; it should run because there are 2 records found as you can see with the print_r output and yet it won't echo the code inside.

Can someone tell me what seems to be the problem, please? Thanks in advance.

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2条回答 默认 最新

  • douxu5845 2015-06-06 04:11
    关注
    $subSpecialties = $this->_db->get('users_subspecialties',array('user_id', '=', $this->_data->id));
    
    print_r($subSpecialties);
    
    foreach ($subSpecialties->results() as $subSpecialty) {
        echo "THIS CODE IS GENERATED FROM INSIDE FOREACH";
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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