如何将query.ajax中的json响应分配给变量？ [重复]

Question

This question already has an answer here:

• How do I return the response from an asynchronous call? 35 answers

I am try to get the json response from a url. Below is the php code which I am requesting to:

if($_POST){
header('Content-type: application/json');
echo '{"hello":"world"}';
}

Below is the javascript I wrote:

$('#site').change(function(){

var result;

$.ajax({
    url: "URL",
    data: { param:value },
    type: "POST",
    dataType: "json",
    success: function(data,textStatus,jqXHR) {

     alert(data['hello']); //output: world
     result = data;

    },

});

    alert(result['hello']); //output: nothing (didn't alert) 
    alert(result); //output: undefined

});

So, my question is how can I assign the data to the result? Thanks.

Edit: My question is duplicated with How to return the response from an AJAX call?

</div>

Answer 1

Put async: false in the ajax attribute

$.ajax({
url: "URL",
data: { param:value },
type: "POST",
dataType: "json",
async: false,
success: function(data,textStatus,jqXHR) {

 alert(data['hello']); //output: world
 result = data;

},

});