匿名函数中的PHP范围问题

Question

so I have these functions

function a(){
    int c = 1;
    b(function(){echo $c;});
}

function b($code){
    $code();
}

but somehow $c becomes undefined in the anonymous function I know it's bacause that the anonymous function is it's own scope, but is there someway to make this work?

Answer 1

Yes: you can use "use" statement.

function a()
{
    $c = 1;
    b(function() use ($c) {
        echo $c;
    });
}

function b($code){
    $code();
}