如何在php中的类构造函数中传递接口实例

Question

I have the following class

class InterfaceImplementation{
    public function __construct(ServiceInterface $oService){
        $this->oService = $oService;
    }
}

When I create the class object

$obj = new InterfaceImplementation();

How to pass the interface instance?And is this the correct way to code?

Answer 1

Any object that will implement ServiceInterface can be used and pass to the constructor. You have to create an instance of the class, but in InterfaceImplementation you will use the interface API (methods declarated in the interface), not the methods from the particular class.