来自PHP脚本的CMD - 获得反馈

Question

I have a LOT ( almost 300 ) old SVN repositories to migrate to git using git2svn.

After considering GOLANG and PYTHON, I finally decided that the easiest way is to use PHP . Might be a bad questionable decision, but it's seemed easy.

So, after 15 minutes , I did have a script that is more or less running ok in tests . Ugly script , but it is a one-timer.

The problem is that the process takes a lot of time , even for simple almost empty repos is can take 30sec. and even a minute. On big ones - even 10min - so before taking it into production, I would like to have some feedback mechanism - so I can actually see what is going on .

..as of now ,the script does output the command feedback like so :

$cmd = "cd ".$GITrepoPath." && svn2git svn://127.0.0.1/". $repoName . " --username " .$SVNusername ." --authors authors.txt --notags --nobranches --notrunk";
            $output = shell_exec($cmd);
            echo "<pre>$output</pre>";

..but this is only after each repo was finished processing .. not like the real cmd execution where I can see the steps .

The only question I found that might be close to what I need was here - but honestly - I did not understood much from the answer ...

I know it is just a one-timer script - but the use case had me interested in how to actually achieve that ( and if it is possible ).

I am on a win7 local machine , but would like to know also for *nix if possible .

Answer 1

shell_exec waits until the process closes. You have to create the process and listen to it, the same as CMD. Use exec function in this way:

$cmd = ''; // your command here
$output_storage = [];
$output_showed = [];
$result = null;
exec($cmd, $output_storage, $result);
while( $result === null ){
    $diff = array_diff($output_storage, $output_showed);
    if( $diff ){
        // all new outputs here as $diff
        $output_showed = $diff;
    }
}