dongxu7408 2016-12-12 09:53
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PHP将天数转换为渐进式dateTime

May be a simple question, but if I have a date say 3rd of December. How could I use php to get that date in a date time format with the current year?

so for 2016 it will be 2016-12-03 and 2017 2017-12-03.

I have a function that needs to calculate the next payment date, and would need to work without magic strings

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  • duanliaoyin3171 2016-12-12 09:59
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    Just use the DateTime object. You get the current year i.e. with the date-function. Or you could also use the DateTime Object again (new DateTime())->format('Y')

    $date = new DateTime();
    $date->setDate(date('Y'), 12, 3);
    echo $date->format('Y-m-d');
    
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