dongzhiyi2006 2015-09-15 21:20
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表单输入不会显示在mysql中

When I submit the following code, the only thing that goes into my database is the second select section (49/43). The other inputs are written into the database with the value "0", no matter what input I submit. I would be very grateful for some help!

<?php 
if ( ! empty( $_POST ) ) {

    $mysqli = new mysqli( 'localhost', 'XXX', 'XXX', 'XXX' );

    if ( $mysqli->connect_error ) {
        die( 'Connect Error: ' . $mysqli->connect_errno . ': ' . $mysqli->connect_error );
    }

    $sql = "INSERT INTO user ( sex, pre, nmbr) VALUES ( '{$mysqli->real_escape_string($_POST['sex'])}', '{$mysqli->real_escape_string($_POST['pre'])}', '{$mysqli->real_escape_string($_POST['nmbr'])}' )";
    $insert = $mysqli->query($sql);

    if ( $insert ) {
        echo "Sucess!";
    } else {
        die("Error: {$mysqli->errno} : {$mysqli_error}");
    }

    $mysqli->close();
}

?>

<form method="post" action="">
        <select name="sex">
            <option>W</option>
            <option>M</option>
        </select>
        <select name="pre">
          <option>+49</option>
          <option>+43</option>
         </select>

        <input name"nmbr" type="text" placeholder=" Deine Handynummer hier eingeben">
        <button> <i class="fa fa-arrow-right"></i></button>
    </form>
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1条回答 默认 最新

  • douyang5943 2015-09-15 21:54
    关注

    With the help of the comment section, this works just fine now.

    Additional info: The column types in the database are VARCHAR for "sex" and "pre" as well as INT for the "nmbr" input. Another sidenote from the comment section: "since you're obviously using everything inside the same file, you need to use isset() and/or !empty() against all your POST arrays."

    <?php 
    if ( ! empty( $_POST ) ) {
    
    
    
        $mysqli = new mysqli( 'localhost', 'XXX', 'XXX', 'XXX' );
    
        if ( $mysqli->connect_error ) {
            die( 'Connect Error: ' . $mysqli->connect_errno . ': ' . $mysqli->connect_error );
        }
    
        $sql = "INSERT INTO user ( sex, pre, nmbr) VALUES ( '{$mysqli->real_escape_string($_POST['sex'])}', '{$mysqli->real_escape_string($_POST['pre'])}', '{$mysqli->real_escape_string($_POST['nmbr'])}' )";
        $insert = $mysqli->query($sql);
    
        if ( $insert ) {
            echo "Success!";
    
        } else {
            die("Error: {$mysqli->errno} : {$mysqli_error}");
        }
    
        $mysqli->close();
    }
    

    ?>

    <form method="post" action="">
            <select name="sex">
                <option>W</option>
                <option>M</option>
            </select>
            <select name="pre">
              <option>+49</option>
              <option>+43</option>
             </select>
    
            <input name="nmbr" type="text" placeholder=" Deine Handynummer hier eingeben">
            <button> <i class="fa fa-arrow-right"></i></button>
        </form>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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