doudanma9706 2018-01-29 07:23 采纳率: 100%
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使用DOMDocument解析HTML时的Rogue元素

Lets assume my $html looks like this:

<!DOCTYPE html>
<html>
<head>
    <script type="text/javascript">document.createElement("video");document.createElement("audio");document.createElement("track");</script>
    <script type="text/javascript" src="/gui/default/tinymcecontent.js"></script>
    <script type="text/javascript" src="/includes/js/video-js/video.min.js"></script>
    <link rel="stylesheet" href="/includes/js/video-js/video-js.css" />
    <script type="text/javascript">document.createElement("video");document.createElement("audio");document.createElement("track");</script>
    <script type"text/javascript" src="/includes/js/video-js/video.js"></script/>
    <link rel="stylesheet" href="/includes/js/video-js/video-js.css" />
</head>
<body style="font-family: arial;font-size: 12px;">
    <p> </p>
    <table width="100%">        
    </table>
</body>
</html>

When I try to parse only elements, that are inside body tag with commands:

$dom = new DOMDocument();

libxml_use_internal_errors(true);
$dom->loadHTML(mb_convert_encoding($html, 'HTML-ENTITIES', 'UTF-8'));
libxml_use_internal_errors(false);

$full_dom = $dom->getElementsByTagName('body')->item(0);

The result of

$dom->saveHTML($full_dom)

is

<body>
<p>\/&gt;<link rel=\"stylesheet\" href=\"\/includes\/js\/video-js\/video-js.css\"><\/p>
<p>\u00a0<\/p>
<table width=\"100%\"><\/table>
<\/body>

Element

<p>\/&gt;<link rel=\"stylesheet\" href=\"\/includes\/js\/video-js\/video-js.css\"><\/p>

comes from where? Everything else is good, just this element gets transfered from head tag into elements of body tag..

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1条回答 默认 最新

  • douxin1163 2018-01-29 07:32
    关注

    It comes from the line :

    <script type"text/javascript" src="/includes/js/video-js/video.js"></script/>

    It is badly formed and should be :

    <script type="text/javascript" src="/includes/js/video-js/video.js"></script>

    You have to check errors after $dom->loadHTML() to see what's happend :

    foreach (libxml_get_errors() as $error) {
    print_r($error);
}
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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