dsy1971 2017-03-21 04:18
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如何获取不在JSON中的列名,但它仍然是我在android中使用PHP收到的数组元素

How can a column name, which is not in JSON but still it is an array element that I have received using PHP in android, be fetched? This is my PHP file:

   {
        "items": [
        {
          "v_id": "1",
          "v_name": "Hotel Girija",
          "v_address": "Vijayanagar Colony, Municipal Colony, Pune,         Maharashtra 411030",
          "v_avg_rating": "3",
          "v_image": "http://i1.walesonline.co.uk/whats-on/food-drink-news/article7978981.ece/ALTERNATES/s615/MAin.jpg",
          "v_contact1": "8456217412"
        },
        {
          "v_id": "4",
          "v_name": "Pataleshwar hotel",
          "v_address": "Some addresss again",
          "v_avg_rating": "5",
          "v_image": "https://www.whatsuplife.in/gurgaon/blog/wp-content/uploads/2015/09/Chaat-Chowk.jpg",
          "v_contact1": "5452232554"
        }
      ],
      "sub_image": "http://www.asiansinamerica.org/wp- content/uploads/2016/08/Asian-and-Chinese-Food.jpg",
      "success": 1
    }

I have to get all values of key items using this :

    JSONObject root = new JSONObject(items);
    JSONArray arr = root.getJSONArray("items");
    for (int i = 0; i < arr.length(); i++)
    {
        JSONObject obj = (JSONObject) arr.get(i);
        path = "" + obj.optString("v_image");
        // path = "http://" + path.replaceAll("\\s+", "%20");
        al_subcatdetl_id.add("" + obj.optString("v_id"));
        al_subcatdetl_name.add("" + obj.optString("v_name"));
        al_subcatdetl_addr.add("" + obj.optString("v_address"));
        al_subcatdetl_img.add("" + path);
        al_subcatdetl_rating.add("" + obj.optString("v_avg_rating"));

       ///al_subject_img.add(obj.getString("sub_image"));
    }

But i don't have any idea how to fetch sub_image, which is outside of items. How can this be achieved?

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1条回答 默认 最新

  • dongyongkui6329 2017-03-21 04:26
    关注

    In these case you can directly get string from JSONObject

    try {    
    JSONObject root = new JSONObject(items);
    String  subimage = root.getString("sub_image");
    } catch(Exception ex){
    
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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