dongmu5106 2017-01-24 10:30
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如何在laravel php内连接表

I have this query which is

SELECT * FROM books b 
INNER JOIN categories c ON b.category_id = c.id 
WHERE c.category_name = 'Comics'

thus is passed by parameter

SELECT * FROM books b 
INNER JOIN categories c ON b.category_id = c.id 
WHERE c.category_name = ?

I tried in Laravel like this

writer::join('categories','categories.id','=','writers.category_id')
  ->where('categories.category_name','Comics')
  ->get();

And with parameter

writer::join('categories','categories.id','=','writers.category_id')
  ->where(['categories.category_name' => $cat])
  ->get();

I didn't get any data in Laravel! Is there any mistake I am doing?

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1条回答 默认 最新

  • dongshaoxiong0012 2017-01-24 10:35
    关注

    Try this instead:

    writer::join('categories','categories.id','=','writers.category_id')
    ->where([
      ['categories.category_name', '=', $cat]
    ])->get();
    

    or

    writer::join('categories','categories.id','=','writers.category_id')
    ->where('categories.category_name', $cat)
    ->get();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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