duanping6698 2016-06-10 12:50
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PDO多个内部联接似乎是循环的

I'm using INNER JOIN for the first time and I'm a little confused.

I have 3 tables:

dog
client
dogclient

I'm trying to get information from both the client and dog tables for every record in the dogclient table. when i do, the result is this:

[{"ID":"1","Name":"Sparky","Forename":"Jamie","Surname":"McAllister"},
{"ID":"1","Name":"Sparky","Forename":"Jamie","Surname":"McAllister"},
{"ID":"2","Name":"Scruff","Forename":"Jamie","Surname":"McAllister"},
{"ID":"2","Name":"Scruff","Forename":"Jamie","Surname":"McAllister"}]

The function i'm using to make this query is:

function getAll(){

    $conn = self::connect();

    $stmt = $conn->prepare("SELECT dog.ID, dog.Name, client.Forename, client.Surname FROM dogclient INNER JOIN client ON dogClient.ClientID INNER JOIN dog ON dogclient.DogID"); 
    $stmt->execute();

    // set the resulting array to associative
    $result = $stmt->setFetchMode(PDO::FETCH_ASSOC); 
    $response = $stmt->fetchAll();

    return $response;

Can anyone see where I've gone wrong?

or, does anyone know a better way to do this?

if it helps, there are only 2 dogs in the dog table, one client in the client table, and 2 records in the dogclient table, so i was expecting 2 results

  • 写回答

1条回答 默认 最新

  • douziqian2871 2016-06-10 13:15
    关注

    Try this:

    INNER JOIN client ON dogClient.ClientID = client.ClientID INNER JOIN dog ON dogclient.DogID = dog.DogID
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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