doutangliang7769 2016-02-20 00:35
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php / fpdf表打印相同的记录

I am trying to print this in pdf

enter image description here

but the records are the same, its odd because they are not the same in my database.

Problem: The records under the criteria, grade and remark are the same but in my database, the are not the same.

this is my code so far:

$sql_criteria = mysql_query("SELECT DISTINCT criteria, percentage  FROM tb_equivalent WHERE instructor_id = '$inst_id' AND description = '$desc' AND subj_code = '$code' AND term = '$term'");
    $criteria = array();
    while($row = mysql_fetch_assoc($sql_criteria)){
        $criteria[] = $row['criteria'];
        $pdf->SetFont('Arial','',9);
        $pdf->Cell(35,5,$row['criteria'],1,'','C');
        $x = $pdf->GetX();
        $y = $pdf->GetY(); 
        $pdf->SetXY($x-35, $y+5); 
        $pdf->Cell(17.5,5,'Ave',1,'','C');
        $pdf->Cell(17.5,5,$row['percentage']."%",1,'','C');
        $pdf->SetXY($x, $y);
    }

    $pdf->Cell(35,10,'Grade',1,0,'C');
    $pdf->Cell(35,10,'Remark',1,0,'C');
    $pdf->SetFont('Arial','',9);
    $pdf->Ln();
    $sql = mysql_query("SELECT * FROM tb_equivalent INNER JOIN tb_student ON tb_equivalent.stud_id=tb_student.stud_id WHERE tb_equivalent.instructor_id = '$inst_id' AND tb_equivalent.description = '$desc' AND tb_equivalent.subj_code = '$code' GROUP BY tb_equivalent.stud_name ORDER BY stud_lname ASC");
    while($row = mysql_fetch_array($sql)){
        $name = $row['stud_name'];
        $course = $row['course_and_year'];
        $pdf->SetFont('Arial','',9);
        $pdf->Cell(1);
        $pdf->Cell(40,4,$name,1);
        $pdf->Cell(20,4,$course,1,0,'C');

        for($x = 0; $x < count($criteria); $x++){
            $query_rec = mysql_query("SELECT * FROM tb_equivalent INNER JOIN tb_student ON tb_equivalent.stud_id=tb_student.stud_id WHERE tb_equivalent.instructor_id = '$inst_id' AND tb_equivalent.criteria = '".$criteria[$x]."' AND tb_equivalent.description = '$desc' AND tb_equivalent.subj_code = '$code' AND tb_equivalent.term = '$term' ORDER BY stud_lname ASC");
            $record = mysql_fetch_array($query_rec);
            $pdf->Cell(17.5,4,$record['average'],1,0,'C');
            $pdf->Cell(17.5,4,$record['equivalent'],1,0,'C');

        }
        $query_grade = mysql_query("SELECT grade, remark FROM tb_record_grade WHERE instructor_id = '$inst_id' AND description = '$desc' AND subj_code = '$code' AND term = '$term'");
        $row_grade = mysql_fetch_array($query_grade);
        $pdf->Cell(35,4,$row_grade['grade'],1,0,'C');
        $pdf->Cell(35,4,$row_grade['remark'],1,0,'C');
        $pdf->Ln();
    }
  • 写回答

1条回答 默认 最新

  • dqiaw48488 2016-02-20 00:44
    关注

    you missed the while loops for the other mysql fetches.

    $stud_id = $row['stud_id'];
    for($x = 0; $x < count($criteria); $x++){
        $query_rec = mysql_query("
            SELECT * 
            FROM tb_equivalent 
            INNER JOIN tb_student ON tb_equivalent.stud_id = tb_student.stud_id 
            WHERE tb_equivalent.instructor_id = '$inst_id' AND tb_equivalent.criteria = '".$criteria[$x]."' 
              AND tb_equivalent.description = '$desc' AND tb_equivalent.subj_code = '$code' AND tb_equivalent.term = '$term'
              AND  tb_equivalent.stud_id = '$stud_id'
        ");
        while ($record = mysql_fetch_array($query_rec)) {
          $pdf->Cell(17.5,4,$record['average'],1,0,'C');
          $pdf->Cell(17.5,4,$record['equivalent'],1,0,'C');
        }
    
    }
    $query_grade = mysql_query("
      SELECT grade, remark 
      FROM tb_record_grade 
      WHERE instructor_id = '$inst_id' AND description = '$desc' AND subj_code = '$code' AND term = '$term'
    ");
    while ($row_grade = mysql_fetch_array($query_grade)) {
      $pdf->Cell(35,4,$row_grade['grade'],1,0,'C');
      $pdf->Cell(35,4,$row_grade['remark'],1,0,'C');
    }
    $pdf->Ln();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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