I want to find interval between dates, the hour function does not work correctly the hour before the time changes. I know there is an answer that partially answers this question here. But it does not answer it according to hours.
I have the following php code:
//helper function to pluralize words
function pluralize( $count, $text ){
return $count . ( ( $count == 1 ) ? ( " $text" ) : ( " ${text}s" ) );
}
/**
* Difference of dates
* @param type $date1 DateTime first date
* @param type $date2 DateTime second date
* @return type string year, month, day, hour, minute, second
*/
function timeDiff($date1, $date2 ){
$string = "";
$interval =$date1->diff($date2);
$suffix = ( $interval->invert ? ' ago' : '' );
if ( $v = $interval->y >= 1 ) $string .= pluralize( $interval->y, 'year' ). ', ';
if ( $v = $interval->m >= 1 ) $string .= pluralize( $interval->m, 'month' ). ', ';
if ( $v = $interval->d >= 1 ) $string .= pluralize( $interval->d, 'day' ). ', ';
if ( $v = $interval->h >= 1 ) $string .= pluralize( ($interval->h), 'hour' ) . ', ';
if ( $v = $interval->i >= 1 ) $string .= pluralize( $interval->i, 'minute' ). ', ';
if ( $v = $interval->i >= 1 ) $string .= pluralize( $interval->s, 'second' ). ' ';
return $string . $suffix;
}
I want the following tests to pass.
$date1 = new DateTime("2014-05-10 20:00:00");
$date2 = new DateTime("2015-11-20 19:45:00");
//This should produce "1 year, 6 months, 9 days, 23 hours, 45 minutes"
//But it does produce "1 year, 6 months, 10 days, 45 minutes"
timeDiff($date1, $date2);
$date3 = new DateTime("2015-11-20 20:00:00");
//This should, and does produce "1 year, 6 months, 10 days"
timeDiff($date1, $date3);
This looks like a version issue pointed out in comments by @John Conde. It is fixed in the new version of PHP 5.4.24 and on. How can I fix this for previous version of PHP?