PHP - 按模式获取dir中的所有文件名

Question

I found this code to iterate through files in folder:

if (is_dir($dir)) {
  if ($dh = opendir($dir)) {
    while (($file = readdir($dh)) !== false) {

          ???????????

  }
    closedir($dh);
}

Files have names like: project-1-0, project-1-1, project-5-14, project-6-21 ... Now I need to filter all files and get only these that begins with "project-1-??" How could I do that, should I use blob() function? Is there any simple example? Im using laravel so maybe there is a function in it for that but i couldnt find something useful

Answer 1

glob is very much what you want here. However, being as you appear to be using Laravel (due to the tag), you should look at Laravel's FileSystem class (accessible using the File facade): 4.2 docs. It provides a wrapper for the standard PHP file functions (though doesn't actually add anything to the mix really for your purposes).

You can do stuff like this:

if (File::isDirectory($dir)) {
    foreach (File::glob($dir.'/project-1-*') as $projectDir) {
        $actualDir = substr($projectDir, strlen($dir) + 1); // trim the base directory
    }
}

But if you want a more powerful file-finding system, you can use Symfony's Finder component (docs), which is already included in your project if you're using Laravel (as some Laravel Filesystem methods use it) and you'll be able to do things like this:

$dirs = Finder::create()->in($dir)->depth(0)->directories()->name('project-1-*');
// or, if you want to use regex, this should work
$dirs = Finder::create()->in($dir)->depth(0)->directories()->name('/^project-1-/');

Now, Finder returns an iterator, so you can use PHP's iterator_to_array function to turn it into an array if you need to use it as an array (that said, an iterator is better if you don't need it as an array, for instance foreaching over it).