dsriya5471 2014-11-27 15:34
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PHPUnit:如何获得CONST的值到模拟?

I want to test this part:

if ($unitOfWork->getEntityState($entity) === $unitOfWork::STATE_NEW) { ....

I already have a MOCK of $unitOfWork. But UnitofWork hast a CONST "STATE_NEW" and I don't know how I can mock this? Because when I say, that method "getEntityState" retuns the value "STATE_NEW", I want to say, that $unitOfWork::STATE_NEW is equal to the return Value and so it is going the if-condition! Has anyone an idea? I already tried:

$unitOfWorkMock->expects($this->once())
            ->method('STATE_NEW')
            ->will($this->returnValue('STATE_NEW'));

...but doesn't work! ALso this ist not possible:

$unitOfWorkMock::STATE_NEW = 2;

To get my Mock of the unitOfWork i Call:

private function getUnitOfWorkMock()
    {
        return $this->getMockBuilder('\Doctrine\ORM\UnitOfWork')
            ->disableOriginalConstructor()
            ->getMock();
    }
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1条回答 默认 最新

  • douao1959 2014-11-28 10:22
    关注

    You don't need to mock constants, as basically mock objects extends the real objects and they have all of their constants.

    $unitOfWorkMock->expects($this->once())
            ->method('getEntityState')
            ->will($this->returnValue($unitOfWorkMock::STATE_NEW));
    
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