duangaoe9401 2013-11-16 06:58
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使用preg_match提取变量

Hi i am having an issue in trying to extract variables using preg replace .I guess i am messing with the delimiters or just doing it wrong

Subject

'file': 'EoWviKqVizQ,end=1384596943/data=B262F941/speed=375k/2305873_hd.flv',

I need to extract

end=1384596943/data=B262F941/speed=375k/1234_hd.flv 

This is basically the string after the comma in between the single quotes.

My attempts

preg_match('#'file':'(.*)'#',$input , $matches)

preg_match("#'file':'(.*)'#",$input , $matches)

Hope someone can help me out

Regards

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  • duanjuebin2519 2013-11-16 07:06
    关注

    Just do this:

    $input = "'file': 'EoWviKqVizQ,end=1384596943/data=B262F941/speed=375k/2305873_hd.flv',";
    $mypart = preg_replace("/^'file': '[^,]+,/", "", $input); // strip first part, i.e., "'file': 'EoWviKqVizQ,"
    $mypart = preg_replace("/',\s*$/", "", $mypart); // strip last part, i.e., "',"
    echo $mypart;
    

    EDITED based on OP feedback (replaced initial [^']+ with file to match only lines starting with 'file', etc.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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