正则表达式 - 在href中匹配标签'a'而不包含http：//

Question

I have for example these "a" tags:

<a href="http://www.domain.com/products/foo">Foo product</a>
<a href="/articles/bar">Bar article</a>

I use this pattern:

/<a\s[^>]*href\s*=\s*(\"??)([^\" >]*?)\\1[^>]*>(.*)<\/a>/siU

This expression returns to me both tags (foo product and bar article). Can you help me please how to make an expression that returns only tag "bar article"?

Thank you.

EDIT:

@Avinash Raj thank you for the tip.

These result of the pattern works for me:

/^.*<a\s[^>]*href="http:\/\/.*$(*SKIP)(*F)|<a\s[^>]*href\s*=\s*(\"??)([^\" >]*?)\1[^>]*>(.*?)<\/a>/miU

Answer 1

Use a DOM parser, such as DOMDocument:

<?php
$site = <<<'EOT'
<a href="http://www.domain.com/products/foo">Foo product</a>
<a href="/articles/bar">Bar article</a>
EOT;

$doc = new DOMDocument();
$doc->loadHTML($site);

$anchors = $doc->getElementsByTagName('a');
foreach ($anchors as $a) {
    $href = $a->getAttribute('href');
    $scheme = parse_url($href, PHP_URL_SCHEME);
    if (!isset($scheme)) {            
        echo $a->textContent;   // output: Bar article
    }
}

Loop through each <a> element. Parse the url, using parse_url. If the scheme isn't set in the href attribute, then echo the content. Of course, what you actually want to do with the element is entirely up to you.