dosgy00204 2014-12-29 00:56
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将对象传递给视图时出错

That's my relevant route:

Route::get('user/{username}/edit', [
    'as'   => 'user.edit',
    'uses' => "UsersController@edit"
]);

and the function:

 public function edit($username)
    {
        $user = User::where('username', '=', $username)->first();
    // dd($user);
        return View::make('user.edit' . ['user' => $user]);
    }

So, in another view I click a button which has the following code:

{{ link_to('user/'.$user->username.'/edit', 'Edit', ['class' => 'btn btn-default']) }}

and it leads me to the correct URL, but throws Array to string conversion exception for this line: return View::make('user.edit' . ['user' => $user]); from the show method. Where I dump the object, right before this line of code, it is correct, populated with values.

It is strange, because I have another method that has the exactly same implementation, but just returns to another view, and it works fine.

Any ideas why am I getting this error?

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1条回答 默认 最新

  • dousikuai5417 2014-12-29 01:01
    关注

    Shouldn't it be

    return View::make('user.edit', ['user' => $user]);
    

    instead of

    return View::make('user.edit' . ['user' => $user]);
    

    ?

    You should pass the data array, not concatenate it to the view name. Concatenating forces the array-to-string conversion.

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