doucheng7534 2014-09-23 04:07
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每个浏览器会话一次弹出cookie

I have a very simple popup, I would like to set a cookie, so when the visitor visits the page / category for the first time he will be able to see the popup and if he navigates out of the page and comes back, the popup won't appear until he ends the session (closes the browser). Thanks!

<script type="text/javascript">
var link;
var element;
t = setTimeout(openPopUp, 3000);

function openPopUp() {
element = document.getElementById("background");
element.style.display = "block";
element = document.getElementById("popup");
element.style.display = "block";
}

function closePopUp() {
element = document.getElementById("popup");
element.style.display = "none";
element = document.getElementById("background");
element.style.display = "none";
}
</script>

Edit: From comments:

var createCookie = Openpopup(name, value, days) {
    var expires;
    if (days) {
        var date = new Date();
        date.setTime(date.getTime() + (60 * 1000));
        expires = ";
        expires = " + date.toGMTString();
    } else {
        expires = "";
    }
    document.cookie = name + "=" + value + expires + ";
    path=/";
} 
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1条回答 默认 最新

  • dougong5285 2014-09-23 08:37
    关注

    Something in the like (untested code):

    var link;
    
    // ....
    
    
    if(getCookie("was_here_before")=="") {
        setTimeout(openPopUp, 3000);
        createCookie("was_here_before", "yes", 1);
    }
    
    // ....
    
    
    
    // these are from SO answer in first comment by Sverri M. Olsen
    // [ http://stackoverflow.com/questions/4825683/how-do-i-create-and-read-a-value-from-cookie ]
    
    
    
    function createCookie(name, value, days) {
        var expires;
        if (days) {
            var date = new Date();
            date.setTime(date.getTime() + (days * 24 * 60 * 60 * 1000));
            expires = "; expires=" + date.toGMTString();
        }
        else {
            expires = "";
        }
        document.cookie = name + "=" + value + expires + "; path=/";
    }
    
    function getCookie(c_name) {
        if (document.cookie.length > 0) {
            c_start = document.cookie.indexOf(c_name + "=");
            if (c_start != -1) {
                c_start = c_start + c_name.length + 1;
                c_end = document.cookie.indexOf(";", c_start);
                if (c_end == -1) {
                    c_end = document.cookie.length;
                }
                return unescape(document.cookie.substring(c_start, c_end));
            }
        }
        return "";
    }
    
    
    // ....
    
    
    function openPopUp(url) {
        var element;
        link = url; // don't know what this is for
        element = document.getElementById("background");
        element.style.display = "block";
        element = document.getElementById("popup");
        element.style.display = "block";
    }
    
    function closePopUp() {
        var element;
        element = document.getElementById("popup");
        element.style.display = "none";
        element = document.getElementById("background");
        element.style.display = "none";
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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