doudao1282 2019-07-06 19:54
浏览 30
已采纳

数据未进入下拉列表

I am trying to fetch some data from my db to a dropdown. But it does not work. This is my code. Thanks

<div class="col-md-5">
   <select multiple class="form-control" style="height: 100px" id="experienceEdit">
     <?php
         $sqlVessel = "SELECT * FROM vessel_types ORDER BY vessel_types ASC";
         $resultVessel = $conn->query($sqlVessel);

         if ($resultVessel->num_rows > 0) {
              // output data of each row
              while ($rowVessel = $resultVessel->fetch_assoc()) {
      ?>
      <option class="experienceValEdit"  value="<?php echo $rowVessel['idvessel_types']; ?>"><?php echo $rowVessel['vessel_types']; ?></option>
      <?php
            }
               } else {

               }
      ?>

  • 写回答

1条回答 默认 最新

  • dongyan3018 2019-07-06 20:32
    关注

    Check this line.

      if ($resultVessel->num_rows > 0) {
    

    There should be a -

    I think this should generate some erros. Isnt it?@usinshif

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 c语言怎么用printf(“\b \b”)与getch()实现黑框里写入与删除?
  • ¥20 怎么用dlib库的算法识别小麦病虫害
  • ¥15 华为ensp模拟器中S5700交换机在配置过程中老是反复重启
  • ¥15 java写代码遇到问题,求帮助
  • ¥15 uniapp uview http 如何实现统一的请求异常信息提示?
  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?